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1.5x^2-5x-15.5=0
a = 1.5; b = -5; c = -15.5;
Δ = b2-4ac
Δ = -52-4·1.5·(-15.5)
Δ = 118
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{118}}{2*1.5}=\frac{5-\sqrt{118}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{118}}{2*1.5}=\frac{5+\sqrt{118}}{3} $
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